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排序链表

2022/12/04

https://leetcode.cn/problems/sort-list/

示例

示例一

输入:head = [4,2,1,3]
输出:[1,2,3,4]

示例二

输入:head = [-1,5,3,4,0]
输出:[-1,0,3,4,5]

示例三

输入:head = []
输出:[]

题解参考

自顶向下归并排序

const merge = (head1, head2) => {
const dummyHead = new ListNode(0);
let temp = dummyHead, temp1 = head1, temp2 = head2;
while (temp1 !== null && temp2 !== null) {
if (temp1.val <= temp2.val) {
temp.next = temp1;
temp1 = temp1.next;
} else {
temp.next = temp2;
temp2 = temp2.next;
}
temp = temp.next;
}
if (temp1 !== null) {
temp.next = temp1;
} else if (temp2 !== null) {
temp.next = temp2;
}
return dummyHead.next;
}

const toSortList = (head, tail) => {
if (head === null) {
return head;
}
if (head.next === tail) {
head.next = null;
return head;
}
let slow = head, fast = head;
while (fast !== tail) {
slow = slow.next;
fast = fast.next;
if (fast !== tail) {
fast = fast.next;
}
}
const mid = slow;
return merge(toSortList(head, mid), toSortList(mid, tail));
}

var sortList = function(head) {
return toSortList(head, null);
};

自底向上归并排序

const merge = (head1, head2) => {
const dummyHead = new ListNode(0);
let temp = dummyHead, temp1 = head1, temp2 = head2;
while (temp1 !== null && temp2 !== null) {
if (temp1.val <= temp2.val) {
temp.next = temp1;
temp1 = temp1.next;
} else {
temp.next = temp2;
temp2 = temp2.next;
}
temp = temp.next;
}
if (temp1 !== null) {
temp.next = temp1;
} else if (temp2 !== null) {
temp.next = temp2;
}
return dummyHead.next;
}

var sortList = function(head) {
if (head === null) {
return head;
}
let length = 0;
let node = head;
while (node !== null) {
length++;
node = node.next;
}
const dummyHead = new ListNode(0, head);
for (let subLength = 1; subLength < length; subLength <<= 1) {
let prev = dummyHead, curr = dummyHead.next;
while (curr !== null) {
let head1 = curr;
for (let i = 1; i < subLength && curr.next !== null; i++) {
curr = curr.next;
}
let head2 = curr.next;
curr.next = null;
curr = head2;
for (let i = 1; i < subLength && curr != null && curr.next !== null; i++) {
curr = curr.next;
}
let next = null;
if (curr !== null) {
next = curr.next;
curr.next = null;
}
const merged = merge(head1, head2);
prev.next = merged;
while (prev.next !== null) {
prev = prev.next;
}
curr = next;
}
}
return dummyHead.next;
};